\(\renewcommand{\Re}{\mathop{\textrm{Re}}}
\renewcommand{\Im}{\mathop{\textrm{Im}}}
\)
Comments on the textbook for Math 407,
Spring 2012
Here are some corrections and amplifications to the textbook,
Schaum's Outline of Complex Variables, second edition, by Murray R. Spiegel, Seymour Lipschutz, John J. Schiller, and Dennis Spellman, McGraw-Hill, 2009, ISBN 9780071615693.
- Section 1.5, formula (2)
- The formula is intended to say that the modulus of a quotient
equals the quotient of the moduli, but the printed formula has the
identical expression on both sides. The formula should read as follows:
\[\left| \frac{z_1}{z_2}\right| = \frac{|z_1|}{|z_2|}
\qquad \text{if \(z_2\ne 0\).}
\]
- Problem 1.65
- The signs are wrong in the formula, which should say that
\(z_1-z_2+z_3-z_4=0\).
- Problem 2.66
- The universal quantifier is misplaced. The problem should say that for
every complex number \(z\), if \(|\sin z|\le 1\), then \(|\Im z|
\le \ln(\sqrt{2}+1)\).
- Problem 3.8, Solution
- At the end of Method 1, notice that the “arbitrary additive constant” is not completely arbitrary: this constant has to be purely imaginary.
- Problem 3.44
- The statement is incomplete. The derivative does exist at one exceptional point: namely, when \(z=0\).
- Problem 3.84
- For \(e^{x^2}\) read \(e^{z^2}\).
- Problem 3.101
- Add the hypothesis that \(f\) is an analytic function.
- Problem 4.43
- The typesetting is ambiguous. The integral is intended to be
\[
\oint_C \frac{dz}{z-2}.
\]
- Problem 5.33
- There is a typographical error in the numerator. For \(\cos\pi2\) read \(\cos\pi z\).
- Problem 6.92
- The answer shown for part (c) has a typographical error: the initial term \(-1/2\) should be \(-1/z\).
- Problem 6.96b
- The answer in the book corresponds to the function \(e^{z^2}/z^3\), not the indicated function \(e^z/z^3\).
- Problem 7.78
- The answer given in the book is \(1/24\), but the correct answer is \(2\pi i/24\), that is, \(\pi i/12\).
- Problem 7.47
- The answer given in the book is \(-6\pi i\), but the correct answer is \(-6\pi^2 i\).
- Problem 8.34b
- The answer given in the book is incorrect. The correct equation is
\(u^2+v^2=u-v\), which represents a circle with center
\((1/2,-1/2)\) and radius \(1/\sqrt{2}\). The circle passes through
the point \(0\), and that point is missing from the image (unless
the \(z\) plane is taken to be the extended complex plane including the point at
infinity).